"The hydraulic load is $H_{load} = 0.37 m \\cdot m^{-2} \\cdot j^{-1}$. The radius $r$ of the collection plate to collect a daily volume of $V$ de 2 L can be calculated as follow."
"The hydraulic load is $H_{load} = 0.37 m \\cdot m^{-2} \\cdot j^{-1}$. The radius $r$ of the collection plate to collect a daily volume of $V$ de 2 L can be calculated as follow.\n",
"\n",
"$$ r = \\sqrt{\\frac{V}{\\pi r}}"
],
],
"metadata": {}
"metadata": {}
},
},
...
...
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# TSS lysimeter
# TSS lysimeter
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## Specifications
## Specifications
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* collect all incoming wastewater during a feeding day in a 2L bottle
* collect all incoming wastewater during a feeding day in a 2L bottle
* removable top plate (through which the water infiltrates)
* removable top plate (through which the water infiltrates)
* preferential flow prevention devices
* preferential flow prevention devices
* adjustable top plate hole size
* adjustable top plate hole size
* weighting device under the sampling bottle
* weighting device under the sampling bottle
* autonomous datalogger
* autonomous datalogger
* perforated bottom under the 2 L bottle
* perforated bottom under the 2 L bottle
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## Calculation of the collection area
## Calculation of the collection area
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The hydraulic load is $H_{load} = 0.37 m \cdot m^{-2} \cdot j^{-1}$. The radius $r$ of the collection plate to collect a daily volume of $V$ de 2 L can be calculated as follow.
The hydraulic load is $H_{load} = 0.37 m \cdot m^{-2} \cdot j^{-1}$. The radius $r$ of the collection plate to collect a daily volume of $V$ de 2 L can be calculated as follow.
$$ r = \sqrt{\frac{V}{\pi r}}
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```
```
import math
import math
H_load = 0.37 # m/m2/j
H_load = 0.37 # m/m2/j
V = 2/1000 # m3
V = 2/1000 # m3
r = math.sqrt(V/H_load/math.pi)
r = math.sqrt(V/H_load/math.pi)
print("The radius must be equal to {} cm.".format(math.floor(r*100)))
print("The radius must be equal to {} cm.".format(math.floor(r*100)))